z^2-12z-160=

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Solution for z^2-12z-160= equation:


Simplifying
z2 + -12z + -160 = 0

Reorder the terms:
-160 + -12z + z2 = 0

Solving
-160 + -12z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(-8 + -1z)(20 + -1z) = 0

Subproblem 1

Set the factor '(-8 + -1z)' equal to zero and attempt to solve: Simplifying -8 + -1z = 0 Solving -8 + -1z = 0 Move all terms containing z to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1z = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1z = 0 + 8 -1z = 0 + 8 Combine like terms: 0 + 8 = 8 -1z = 8 Divide each side by '-1'. z = -8 Simplifying z = -8

Subproblem 2

Set the factor '(20 + -1z)' equal to zero and attempt to solve: Simplifying 20 + -1z = 0 Solving 20 + -1z = 0 Move all terms containing z to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1z = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1z = 0 + -20 -1z = 0 + -20 Combine like terms: 0 + -20 = -20 -1z = -20 Divide each side by '-1'. z = 20 Simplifying z = 20

Solution

z = {-8, 20}

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